A 81.9 kg person stands on her toes. The surface area of her toes in contact with the ground is only 0.00210 m^2. How much pressure is exerted between her toes and the ground, IN ATMOSPHERES?

So, the pressure exerted by the person on the ground (in units of atm) is close to 0.38 atm.
Hi ! I'm Deva from Brainly Indonesia and I will help explain something about solid pressure material. Remember the definition of pressure in solids is "The amount of force felt per unit area of pressure". So, based on the meaning, it is embodied in the equation :
[tex] \boxed{\sf{\bold{P = \frac{F}{A}}}} [/tex]
[tex] \boxed{\sf{\bold{F = P \times A}}} [/tex]
[tex] \boxed{\sf{\bold{A = \frac{F}{P}}}} [/tex]
With the following conditions :
However, always remember, if the object is a stationary mass and is affected by gravity, then the value of F can be calculated by :
[tex] \boxed{\sf{\bold{F = m \times g}}} [/tex]
With the following conditions :
We know that :
What is ask :
Step by step :
[tex] \sf{P = \frac{F}{A}} [/tex]
[tex] \sf{P = \frac{m \times g}{A}} [/tex]
[tex] \sf{P = \frac{81.9 \times 9.8}{0.0210}} [/tex]
[tex] \sf{P = \frac{802.62}{0.0210}} [/tex]
[tex] \sf{P = 38,220 \: N/m^2} [/tex]
[tex] \sf{P_{(atm)} = \frac{38,220}{101,325}} [/tex]
[tex] \sf{P_{(atm)} = \frac{38,220}{101,325}} [/tex]
[tex] \boxed{\sf{P_{(atm)} \approx 0,38 \: atm}} [/tex]
So, the pressure exerted by the person on the ground (in units of atm) is close to 0.38 atm.