A 81.9 kg person stands on her toes. The surface area of her toes in contact with the ground is only 0.00210 m^2. How much pressure is exerted between her toes and the ground, IN ATMOSPHERES?

A 819 kg person stands on her toes The surface area of her toes in contact with the ground is only 000210 m2 How much pressure is exerted between her toes and t class=

Respuesta :

So, the pressure exerted by the person on the ground (in units of atm) is close to 0.38 atm.

Introduction

Hi ! I'm Deva from Brainly Indonesia and I will help explain something about solid pressure material. Remember the definition of pressure in solids is "The amount of force felt per unit area of pressure". So, based on the meaning, it is embodied in the equation :

[tex] \boxed{\sf{\bold{P = \frac{F}{A}}}} [/tex]

[tex] \boxed{\sf{\bold{F = P \times A}}} [/tex]

[tex] \boxed{\sf{\bold{A = \frac{F}{P}}}} [/tex]

With the following conditions :

  • P = solid pressure (N/m²)
  • F = the force that the object has (N)
  • A = Area of pressure (m²)

However, always remember, if the object is a stationary mass and is affected by gravity, then the value of F can be calculated by :

[tex] \boxed{\sf{\bold{F = m \times g}}} [/tex]

With the following conditions :

  • m = mass of the object (kg)
  • g = acceleration due to gravity (m/s²)

Problem Solving

We know that :

  • m = mass of the object = 81.9 kg
  • g = acceleration due to gravity = 9.8 m/s²
  • A = Area of pressure = 0.00210 m² >> See, in the problem there is the word "toes" which means this area has covered the whole (his/her ten of toes)

What is ask :

  • P = solid pressure = ... atm

Step by step :

  • Calculate the pressure value, meanwhile, the unit is N/m²

[tex] \sf{P = \frac{F}{A}} [/tex]

[tex] \sf{P = \frac{m \times g}{A}} [/tex]

[tex] \sf{P = \frac{81.9 \times 9.8}{0.0210}} [/tex]

[tex] \sf{P = \frac{802.62}{0.0210}} [/tex]

[tex] \sf{P = 38,220 \: N/m^2} [/tex]

  • Don't forget to convert N/m² to atm, 1 atm = 101,325 N/m²

[tex] \sf{P_{(atm)} = \frac{38,220}{101,325}} [/tex]

[tex] \sf{P_{(atm)} = \frac{38,220}{101,325}} [/tex]

[tex] \boxed{\sf{P_{(atm)} \approx 0,38 \: atm}} [/tex]

So, the pressure exerted by the person on the ground (in units of atm) is close to 0.38 atm.

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