Answer
given,
displacement wave function
s(x, t) = 2.00 cos (15.7 x + 858 t)
now, comparing the wave equation with general equation.
s(x, t) = A cos (k x + ω t)
where A is the amplitude of the wave in micrometer.
now,
a) Amplitude of the wave
A = 2 x 10⁻⁶ μ m
b) [tex]\lambda = \dfrac{2\pi}{k}[/tex]
k = 15.7 m
[tex]\lambda = \dfrac{2\pi}{15.7}[/tex]
λ = 0.4 m
c) wave speed
[tex]v = \dfrac{\omega}{k}[/tex]
[tex]v = \dfrac{858}{15.7}[/tex]
v = 54.65 m/s
d) For instantaneous displacement
Assuming the position and time is given as
x = 0.05 m and t = 3 m s
now,
s(x, t) = 2.00 cos (15.7 x 0.05 + 858 x 3 x 10⁻³ )
s(x, t) = 2.00 cos (3.359)
s(x,t) = -1.95 μ m