Respuesta :
Answer with Explanation:
We are given that
Dipole moment=[tex]0.5 e nm=0.5\times 1.6\times 10^{-19}\times 10^{-9}=0.8\times 10^{-28}[/tex]C-m
Because [tex]1 e=1.6\times 10^{-19} C[/tex]
[tex]1 nm=10^{-9} m[/tex]
[tex]a^x\cdot a^y=a^{x+y}[/tex]
Magnitude of electric field,E=[tex]8\times 10^4[/tex] N/C
a.We have to find the magnitude of torque on the dipole when
dipole is parallel to the electric field
i.e[tex]\theta=0[/tex]
We know that
[tex]\tau=PEsin\theta[/tex]
Substitute the values then we get
[tex]\tau=0.8\times 10^{-28}\times 8\times 10^{4} sin0=0[/tex]
Because sin 0=0
[tex]\tau=0[/tex]
b.[tex]\theta=90^{\circ}[/tex]
[tex]\tau=0.8\times 10^{-28}\times 8\times 10^4sin90[/tex]
By using [tex]sin90^{\circ}=1[/tex]
[tex]\tau=6.4\times 10^{-28+4}=6.4\times 10^{-24}Nm[/tex]
[tex]\tau=6.4\times 10^{-24}[/tex]Nm
c.[tex]\theta=30^{\circ}[/tex]
[tex]\tau=0.8\times 10^{-28}\times 8\times 10^4sin 30[/tex]
[tex]\tau=6.4\times 10^{-24}\times \frac{1}{2}[/tex] Nm
By using [tex] sin30^{\circ}=\frac{1}{2}[/tex]
[tex]tau=3.2\times 10^{-24} Nm[/tex]
d.Potential energy, U=[tex]-PEcos\theta[/tex]
[tex]\theta=0[/tex]
[tex]U=-0.8\times 10^{-28}\times 8\times 10^4cos 0=-6.4\times 10^{-28}J[/tex]
Because cos 0degree=1
By having the p, E, and anglёs, we can calculate the τ value and the U values. a) 0 Nm, b) 6.4x10⁻²⁴ Nm, c) 3.2x10⁻²⁴ Nm. d) U = 6.4x10⁻²⁴, U = 0, U = 5.57x10⁻²⁴
First, we need to change the units of the given dip0lё momёnt, p.
The result is
p = 0.8 x 10 ⁻²⁸ Cm
Now we can calculate the t0rquё values.
T0rque, t = p x E x sёn θ
The results are
a) τ = 0 Nm
b) τ = 6.4x10⁻²⁴ Nm
c) τ = 3.2x10⁻²⁴ Nm
d)
p0tёntial energy, U = p x E x c0s θ
- U = 6.4x10⁻²⁴
- U = 0
- U = 5.57x10⁻²⁴
You will find the complete explanation in the attached files
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