Question

If the swan must reach a speed of 4.7 m/s to take off and it accelerates from rest at a constant rate of 0.45 m/s2, how far, in meters, will it travel before becoming airborne

Answer 1

Answer:

24.54 m

Explanation:

From the following equation of motion, we can calculate the time it takes for the swan to reach the speed of 4.7m/s from rest at an acceleration of 0.45 m/s2:

$v = v_0 + at$

where v is the final speed, v0 = 0 m/s is the initial speed at rest, a is the acceleration and t is the time it takes

$4.7 = 0 + 0.45t$

$0.45t = 4.7$

$t = 4.7 / 0.45 = 10.44 s$

And the distance it covered within 10.44 s is

$s = at^2/2 = 0.45*10.44^2/2 = 24.54 m$