The solution to given system of equations is x = 2 and y = -5
Solution:
Given the system of equations are:
4x + y = 3 ---------- eqn 1
-2x + 3y = -19 ---------- eqn 2
We have to find the solution to above system of equations
We can solve the system by substitution method
From eqn 1,
4x + y = 3
Isolate y to one side
y = 3 - 4x ----------- eqn 3
Substitute eqn 3 in eqn 2
-2x + 3(3 - 4x) = -19
-2x + 9 - 12x = -19
Combine the like terms
-14x = -19 - 9
-14x = -28
Divide both sides of equation by -14
x = 2
Substitute x = 2 in eqn 3
y = 3 - 4(2)
y = 3 - 8
y = -5
Thus the solution is x = 2 and y = -5
