The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(aP − b), where a and b are positive constants. Discuss what happens to the population P as time t increases.

Respuesta :

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

[tex]dP/dt=P(aP-b)[/tex]

[tex]dP=P(aP-b)dt[/tex]

[tex]1/(dP^2-bP)dP=dt[/tex]

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

[tex]1/(d-b/P)\cdot{P^2} dP[/tex]

let

[tex]u=d-b/P[/tex]

[tex]du/dP=b/P^2[/tex]

[tex]dP=[/tex][tex]\int\limits {P^2/b} \, du[/tex]

[tex]P=lnu/b[/tex]

Substitute u in:

[tex]P=ln(d-b/P)/b[/tex]

Therefore the equation is:

[tex]ln(d-b/P)/b=t[/tex]

We simplify:

[tex]d-b/P=e^b^t[/tex]

[tex]P=b/(d-e^b^t)[/tex]

As t increases to infinity P will decrease

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