Question

Two steamrollers begin 105 m apart and head toward each other, each at a constant speed of 1.30 m/s . At the same instant, a fly that travels at a constant speed of 2.40 m/s starts from the front roller of the southbound steamroller and flies to the front roller of the northbound one, then turns around and flies to the front roller of the southbound once again, and continues in this way until it is crushed between the steamrollers in a collision.What distance does the fly travel?

Answer 1

The required distance will be "96.94 m".

According to the question,

Object's relative speed,

$v_{rel} = 1.30+1.30$

      $= 2.60 \ m/s$

Time taken by the two steamrollers,

$t = \frac{d}{v_{rel}}$

  $= \frac{105}{2.60}$

  $= 40.39 \ seconds$

hence,

The distance of fly travel will be:

→ $s = vt$

By putting the values,

     $= 2.40\times 40.39$

     $= 96.94 \ m$

Thus the above response is right.

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