Question

function f has f(10)=20,f′(10)=2 and f′′(x)<0, for x≥10. Which of the following are possible values for f(14)?
f(14) = 20.28 is
f(14) = 20.14 is
f(14) = 20.56 is

Answer 1

Answer:

f(14) = 28

Step-by-step explanation:

The function that satisfy the equations is

f(x) = 3x - x

f(10) = 3*10 - 10 = 30 - 10 = 20

f'(x) = 3 - 1 = 2.

Therefore,

f(14) = 3(14) - 14 = 42 - 14 = 28.

f(14) = 28