Answer:
[tex]h(0)=400[/tex]
The above function value for [tex]h(0)[/tex] shows that height of the ball before it was dropped i.e. at time = 0 seconds.
The height of the ball above the ground before it was dropped = 400 ft.
Step-by-step explanation:
Given:
The quadratic function that models the height of the baseball above the ground in feet , [tex]t[/tex] seconds after it was dropped is given as:
[tex]h(t)=-16t^2+400[/tex]
To find [tex]h(0)[/tex] and interpret the meaning of the function value in contect of the problem.
Solution:
In order to find [tex]h(0)[/tex], we will replace [tex]t=0[/tex] in the given function as [tex]h(t)[/tex] is a function of time [tex]t[/tex].
Thus, we have:
[tex]h(0)=-16(0)^2+400[/tex]
[tex]h(0)=16(0)+400[/tex]
[tex]h(0)=0+400[/tex]
[tex]h(0)=400[/tex] (Answer)
The above function value for [tex]h(0)[/tex] shows that height of the ball before it was dropped i.e. at time = 0 seconds.
The height of the ball above the ground before it was dropped = 400 ft.