Respuesta :
First represent your 3 consecutive integers as follows.
X ⇒ first integer
X + 1 ⇒ second integer
X + 2 ⇒ third integer
Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.
Simplifying on the left side we get 3x + 3 = 84.
Now subtract 3 from both sides to get 3x = 81.
Dividing both sides by 3, we find that x = 27.
Finally, make sure you list all your answers.
If x is 27 then x + 1 is 28 and x + 2 is 29.
Answer:
27 + 28 + 29 = 84
Step-by-step explanation:
Let the three consecutive integers be x +1, x+2 and x+3
Thus,
[tex](x + 1) + (x + 2) + (x + 3) = 84[/tex]
Remove the brackets
[tex]x + 1 + x + 2 + x + 3 = 84[/tex]
Group the like terms
[tex]x + x + x + 1 + 2 + 3 = 84[/tex]
[tex]3x + 6 = 84[/tex]
To make 3x subject of formula, subtract 6 from both sides of the equation thus,
[tex]3x + 6 - 6 = 84 - 6[/tex]
[tex]3x = 78[/tex]
Divide through by 3
[tex] \frac{3x}{3} = \frac{78}{3} [/tex]
[tex]x = 26[/tex]
Since x = 26
[tex]x + 1 = 26 + 1 = 27[/tex]
[tex]x + 2 = 26 + 2 = 28[/tex]
[tex]x + 3 = 26 + 3 = 29[/tex]
Therefore, the three consecutive integers are 27, 28 and 29
Check
[tex]27 + 28 + 29 = 84[/tex]