Respuesta :

First represent your 3 consecutive integers as follows.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.

Simplifying on the left side we get 3x + 3 = 84.

Now subtract 3 from both sides to get 3x = 81.

Dividing both sides by 3, we find that x = 27.

Finally, make sure you list all your answers.

If x is 27 then x + 1 is 28 and x + 2 is 29.

Answer:

27 + 28 + 29 = 84

Step-by-step explanation:

Let the three consecutive integers be x +1, x+2 and x+3

Thus,

[tex](x + 1) + (x + 2) + (x + 3) = 84[/tex]

Remove the brackets

[tex]x + 1 + x + 2 + x + 3 = 84[/tex]

Group the like terms

[tex]x + x + x + 1 + 2 + 3 = 84[/tex]

[tex]3x + 6 = 84[/tex]

To make 3x subject of formula, subtract 6 from both sides of the equation thus,

[tex]3x + 6 - 6 = 84 - 6[/tex]

[tex]3x = 78[/tex]

Divide through by 3

[tex] \frac{3x}{3} = \frac{78}{3} [/tex]

[tex]x = 26[/tex]

Since x = 26

[tex]x + 1 = 26 + 1 = 27[/tex]

[tex]x + 2 = 26 + 2 = 28[/tex]

[tex]x + 3 = 26 + 3 = 29[/tex]

Therefore, the three consecutive integers are 27, 28 and 29

Check

[tex]27 + 28 + 29 = 84[/tex]

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