y - 6 = -3(x + 5) is the equation of the line that has a slope of -3 and goes through the point (-5, 6) in point-slope form
Solution:
Given that we have to write the equation of the line that has a slope of -3 and goes through the point (-5, 6) in point-slope form
The equation of line in point slope form is given as:
[tex]y - y_1=m(x-x_1)[/tex]
Where, "m" is the slope of line
Here in this sum,
slope = m = -3
[tex](x_1, y_1) = (-5, 6)[/tex]
Substituting the values in formula we get,
[tex]y - 6 = -3(x-(-5))\\\\y-6=-3(x+5)[/tex]
Thus the equation of line in point slope form is found