Question

After crossing true-breeding yellow and green pea plants, Mendel allowed the yellow F1 plants to self. As a result of this F1 self-cross, he observed 5920 yellow peas and 2103 green pea plants. Determine whether or not these data are consistent with his law of equal segregation.

Answer 1

Answer:

The data are not consistent with law of equal segregation.

Explanation:

According to law of segregation, the ratio of yellow peas to green peas at F2 should be 3:1.

                                             yellow                    green

Observed frequencies          5920                      2103

Expected frequency        $\frac{3}{4}*8023$ = 6017.25        $\frac{1}{4} * 8023$ = 2005.75

Using Chi square($X^2$):

   $X^2$ yellow = $\frac{(observed frequency - expected frequency)^2}{expected frequency}$

                        = $\frac{(5920 - 6017.25)^2}{6017.25}$

                                   = 1.57

    $X^2$ green =  $\frac{(2103 - 2005.75 )^2}{2005.75 }$

                        =   4.72

$X^2$ total = 1.57 + 4.72 = 6.29

Degree of freedom = 2 - 1 = 1

$X^2$ tabulated (α = 0.05) = 3.841

The calculated Chi square value is more than the tabulated Chi square value, hence, the conclusion is that the data are not consistent with law of segregation.