Answer:
x = 3 , x= 0
Step-by-step explanation:
Given:
3x minus x squared
To Find;
The value of X= ?
Solution:
3x minus x squared = [tex]3x -x^2[/tex]
Writin in the standard form, we get
[tex]-x^2 +3x + 0[/tex]
Now lets us the quadratic formula to find the value of x
x = [tex]\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]
here
a = -1
b = 3
c = 0
On substituting the values
x = [tex]\frac{-3 \pm \sqrt{(3)^2 -4(-1)(0)}}{2(-1)}[/tex]
x = [tex]\frac{-3 \pm \sqrt{9 -0}}{-2}[/tex]
x = [tex]\frac{-3 \pm \sqrt{9 }}{-2}[/tex]
x = [tex]\frac{-3 \pm 3}{-2}[/tex]
x = [tex]\frac{-3-3}{-2}[/tex] x = [tex]\frac{-3+3}{-2}[/tex]
x =[tex]\frac{-6}{-2}[/tex] x =[tex]\frac{0}{2}[/tex]
x = 3 x = 0
Thus x = 3 or x = 0