Respuesta :

Answer:

x = 3 , x= 0

Step-by-step explanation:

Given:

3x minus x squared

To Find;

The value of X= ?

Solution:

3x minus x squared = [tex]3x -x^2[/tex]

Writin in the standard form, we get

[tex]-x^2 +3x + 0[/tex]

Now lets us the quadratic formula to find the value of x

x = [tex]\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

here  

a =  -1

b = 3

c = 0

On substituting the values

x = [tex]\frac{-3 \pm \sqrt{(3)^2 -4(-1)(0)}}{2(-1)}[/tex]

x = [tex]\frac{-3 \pm \sqrt{9 -0}}{-2}[/tex]

x = [tex]\frac{-3 \pm \sqrt{9 }}{-2}[/tex]

x = [tex]\frac{-3 \pm 3}{-2}[/tex]

x = [tex]\frac{-3-3}{-2}[/tex]                                      x = [tex]\frac{-3+3}{-2}[/tex]

x =[tex]\frac{-6}{-2}[/tex]                                           x =[tex]\frac{0}{2}[/tex]

x = 3                                            x = 0

Thus x = 3 or x = 0

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