The frequency of wave B is half the frequency of wave A
Explanation:
The wavelength, the speed and the frequency of a wave are related by the wave equation:
[tex]v=f \lambda[/tex]
where
v is the speed of the wave
f is its frequency
[tex]\lambda[/tex] is its wavelength
The equation can also be rewritten as
[tex]f=\frac{v}{\lambda}[/tex]
In this problem, we have wave A with wavelength [tex]\lambda_A[/tex] and speed v, so its frequency is
[tex]f_A=\frac{v}{\lambda_A}[/tex]
Then we have wave B, whose wavelength is twice that of wave A:
[tex]\lambda_B = 2 \lambda_A[/tex]
And its speed is the same; Therefore, its frequency is
[tex]f_B = \frac{v}{\lambda_B}=\frac{v}{2\lambda_A}=\frac{1}{2}(\frac{v}{\lambda_A})=\frac{f_A}{2}[/tex]
So, the frequency of wave B is half that of wave A.
Learn more about wavelength and frequency:
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