The question is incomplete, here is the complete question:
Suppose the reaction is:
[tex]A+2B\rightarrow C[/tex]
If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed
Answer: The maximum amount of C produced will be 1 mole
Explanation:
We are given:
Moles of A = 6 moles
Moles of B = 2 moles
For the given chemical reaction:
[tex]A+2B\rightarrow C[/tex]
By Stoichiometry of the reaction:
2 moles of B reacts with 1 mole of A
So, 2 moles of B will react with = [tex]\frac{1}{2}\times 2=1[/tex] mole of A
As, As, given amount of A is more than the required amount. So, it is considered as an excess reagent.
Thus, B is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of B produces 1 mole of C
So, 2 moles of given B will produce [tex]=\frac{1}{2}\times 2=1mol[/tex] of C
Hence, the maximum amount of C produced will be 1 mole