antonypaz5787 antonypaz5787

27-01-2020
Chemistry

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How many grams of magnesium bromide, MgBr2, must be dissolved to prepare 400. mL of a 0.183 M aqueous solution of the salt?

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Eduard22sly Eduard22sly

27-01-2020

Answer: 13.47g of MgBr2

Explanation:

MM of MgBr2 = 24 + (2 x 80) = 24 + 160 = 184g/mol

Mass conc. Of MgBr2 = 0.183 x184 = 33.672g

33.672g of MgBr2 dissolves in 1000mL

Therefore Xg of MgBr2 will dissolve in 400mL

Xg of MgBr2 = ( 33.672 x 400)/1000

Xg of MgBr2 = 13.47g

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