Answer:
[tex]sin ( u +\frac{\pi}{2} ) = cos (u)[/tex]
Step-by-step explanation:
Let us use the identity
sin(A+B)= cos(A) sin(B)+cos (B) sin(A) to simplify the given expression
Then
[tex]sin(u + \frac{\pi}{2})= \cos \left(u\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(u\right)[/tex]--------------------(1)
Here
[tex]cos (\frac{\pi}{2}) = 0\\[/tex]---------------------(2)
[tex]sin(\frac{\pi}{2})= 1[/tex]---------------------(3)
Substituting the values in (1)
[tex]sin(u + \frac{\pi}{2})= \cos \left(u\right)(1)+(0)\sin \left(u\right)[/tex]
[tex]sin(u + \frac{\pi}{2})= \cos \left(u\right) + 0[/tex]
[tex]sin(u + \frac{\pi}{2})= \cos \left(u\right)[/tex]