Question

A solution is made by mixing of acetic acid and of acetone . Calculate the mole fraction of acetic acid in this solution. Round your answer to significant digits.

Answer 1

The question is incomplete, here is the complete question:

A solution is made by mixing 103. g of acetone and 137. g of acetic acid. Calculate the mole fraction of acetic acid in this solution. Round your answer to 3 significant digits.

Answer: The mole fraction of acetone in the solution is 0.438

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

• For acetic acid:

Given mass of acetic acid = 137. g

Molar mass of acetic acid = 60 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic acid}=\frac{137g}{60g/mol}=2.283mol$

• For acetone:

Given mass of acetone = 103. g

Molar mass of acetone = 58 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic acid}=\frac{137g}{60g/mol}=1.78mol$

To calculate the mole fraction, we use the equation:

$\chi_A=\frac{n_A}{n_A+n_B}$

Calculating the mole fraction of acetone:

$\chi_{\text{acetone}}=\frac{n_{\text{acetone}}}{n_{\text{acetone}}+n_{\text{acetic acid}}}$

$\chi_{\text{acetone}}=\frac{1.78}{1.78+2.283}\\\\\chi_{\text{acetone}}=0.438$

Hence, the mole fraction of acetone in the solution is 0.438