Question

Suppose y varies jointly with x and z. If y=20 when x=2 and z=5, find y when x=14 and z=8.

Answer 1

Answer:

K=2, y=224

Step-by-step explanation:

Y(proportional sign)xz

Y=kxz

20=k×2×5

10k=20

K=2

Find y when x=14andz=8

Y=2xz

Y=2×14×8

Y=224

Answer 2

The value of y given the joint variation, where y = kxz is: 224.

Recall:

• Joint variation can be modelled with the equation, y = kxz

• k = constant of proportionality

Thus, given that y = kxz, substitute y = 20, x = 2, and z = 5 into y = kxz and solve for k.

$20 = k(2)(5)\\\\20 = k10$

• Divide both sides by 10

k = 2

To find y, substitute k = 2, x = 14, and z = 8 into y = kxz

• Thus:

$y = (2)(14)(8)\\\\\mathbf{y = 224}$

• Therefore, the value of y given the joint variation, where y = kxz is: 224.

Learn more here:

https://brainly.com/question/14629028