Question

A particle is being accelerated through space by a 10-N force. Suddenly the particle encounters a head-on second force of 10 N in the opposite direction. The particle with both forces acting on it_____________.

Answer 1

The particle with both forces acting on it will move at constant velocity

Explanation:

We can solve this problem by applying Newton's second law of motion, which states that the net force acting on a body is equal to the product between its mass and its acceleration:

$F=ma$

where

F is the net force

m is the mass

a is the acceleration

For the particle in this problem, initially it has a forward force of

$F_1 = 10 N$

Later, it encounters a second additional force in the opposite direction, therefore

$F_2 = -10 N$

This means that the net force on the particle now is

$F=F_1+F_2 = +10 +(-10) = 0$

As a consequence, the acceleration of the particle is zero:

$a=0$

And this means that the particle moves with constant velocity.

Learn more about Newton's second law:

brainly.com/question/3820012

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