Answer:
[tex]F=52.1301\ N[/tex]
Explanation:
Given:
function of height of the mass connected via a rope:
differentiate the above eq. with respect to time t gives us the velocity in vertical direction:
[tex]v_y=\frac{d}{dt} y[/tex]
[tex]v_y=2.8+1.83\ t^2[/tex]
put the value of given time:
[tex]v_y=2.8+1.83\times 4.4^2[/tex]
[tex]v_y=38.2288\ m.s^{-1}[/tex]
[tex]F=\frac{\Delta (m.v_y)}{t}[/tex]
[tex]F=\frac{6\times 38.2288}{4.4}[/tex]
[tex]F=52.1301\ N[/tex]