Respuesta :

The ODE has characteristic equation

[tex]r^2+6r+9=(r+3)^2=0[/tex]

with roots [tex]r=-3[/tex], and hence the characteristic solution

[tex]y_c=C_1e^{-3t}+C_2te^{-3t}[/tex]

For the particular solution, assume an ansatz of [tex]y_p=ae^{-t}[/tex], with derivatives

[tex]\dfrac{\mathrm dy_p}{\mathrm dt}=-ae^{-t}[/tex]

[tex]\dfrac{\mathrm d^2y_p}{\mathrm dt^2}=ae^{-t}[/tex]

Substituting these into the ODE gives

[tex]ae^{-t}-6ae^{-t}+9ae^{-t}=4ae^{-t}=4e^{-t}\implies a=1[/tex]

so that the particular solution is

[tex]\boxed{y(t)=C_1e^{-3t}+C_2te^{-3t}+e^{-t}}[/tex]

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