Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4r units. The base of cylinder B has an
area of 9. units
The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

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Question:

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

Answer:

Dimensions of cylinder A are multiplied by [tex]\frac{3}{2}[/tex]  to produce the corresponding dimensions of cylinder B

Solution:

Given that, Cylinders A and B are similar solids

The base of cylinder A has a circumference of [tex]4 \pi[/tex] units

The formula for the circumference of a circle is:

[tex]C = 2 \pi r[/tex]

where, "r" is the radius of circle

[tex]4 \pi = 2 \pi r[/tex]

r = 2

Thus, radius of cylinder A = 2 units

The base of cylinder B has an  area of [tex]9 \pi[/tex] units

The area of circle is given by formula:

[tex]Area = \pi r^2[/tex]

where, "r" is the radius of circle

[tex]9 \pi = \pi r^2\\\\r^2 = 9\\\\r = 3[/tex]

Thus radius of cylinder B is 3 units

Let the multiplication factor be "x"

From given,

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore,

[tex]Radius\ of\ Cylinder\ A = x \times Radius\ of\ Cylinder\ B\\\\2 \times x = 3\\\\x = \frac{3}{2}[/tex]

Thus dimensions of cylinder A are multiplied by [tex]\frac{3}{2}[/tex]  to produce the corresponding dimensions of cylinder B

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