Respuesta :
The electric potential energy is [tex]1\cdot 10^{-7} J[/tex]
Explanation:
The electric potential energy stored in a capacitor is given by the equation
[tex]PE=Q \Delta V[/tex]
where
Q is the charge stored in the capacitor
[tex]\Delta V[/tex] is the potential difference between the plates
For the capacitor in this problem, we have
[tex]Q=4.0\cdot 10^{-10}C[/tex] is the charge
[tex]\Delta V=250.0 V[/tex] is the potential difference
Substituting, we find the potential energy:
[tex]PE=(4.0\cdot 10^{-10})(250.0)=1\cdot 10^{-7} J[/tex]
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