Calculate the electric potential energy in a capacitor that stores 4.0 x 10-10 C
of charge at 250.0 V. Use PE. = "QAV.

Respuesta :

The electric potential energy is [tex]1\cdot 10^{-7} J[/tex]

Explanation:

The electric potential energy stored in a capacitor is given by the equation

[tex]PE=Q \Delta V[/tex]

where

Q is the charge stored in the capacitor

[tex]\Delta V[/tex] is the potential difference between the plates

For the capacitor in this problem, we have

[tex]Q=4.0\cdot 10^{-10}C[/tex] is the charge

[tex]\Delta V=250.0 V[/tex] is the potential difference

Substituting, we find the potential energy:

[tex]PE=(4.0\cdot 10^{-10})(250.0)=1\cdot 10^{-7} J[/tex]

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5.0•10^-8J

Ape.x .........-_-

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