Question

If p(x) = x2 – 1 and q (x) = 5 (x minus 1), which expression is equivalent to (p – q)(x)?
5(x – 1) – x2 – 1
(5x – 1) – (x2 – 1)
(x2 – 1) – 5(x – 1)
(x2 – 1) – 5x – 1

Answer 1

Answer:

Step-by-step explanation:

p(x) = x^2 - 1

q(x) = 5(x - 1)

(p - q)(x) = x^2 - 1 - 5(x - 1)

Answer 2

Answer:

c. (x^2-1)-5(x-1)

Step-by-step explanation:

on edge 2020 !