Answer:
(A) [tex]a=2.0.37m/sec^2[/tex]
(B) s = 146.664 m
Explanation:
We have given car starts from the rest so initial velocity u = 0 m /sec
Final velocity v = 88 km/hr
We know that 1 km = 1000 m
And 1 hour = 3600 sec
So [tex]88km/hr=88\times \frac{1000}{3600}=24.444m/sec[/tex]
Time is given t = 12 sec
(A) From first equation of motion v = u+at
So [tex]24.444=0+a\times 12[/tex]
[tex]a=2.0.37m/sec^2[/tex]
So acceleration of the car will be [tex]a=2.0.37m/sec^2[/tex]
(b) From third equation of motion [tex]v^2=u^2+2as[/tex]
So [tex]24.444^2=0^2+2\times 2.037\times s[/tex]
s = 146.664 m
Distance traveled by the car in this interval will be 146.664 m