Which of the following is equal to the rational expression when X not equal -4 or 3?
x2 - 4x + 3
X^2+ X - 12

Answer:
A
Step-by-step explanation:
Given
[tex]\frac{x^2-4x+3}{x^2+x-12}[/tex]
Factorise the numerator and denominator
x² - 4x + 3 = (x - 1)(x - 3)
x² + x - 12 = (x + 4)(x - 3), thus
= [tex]\frac{(x-1)(x-3)}{(x+4)(x-3)}[/tex] ← cancel (x - 3) on numerator/denominator
= [tex]\frac{x-1}{x+4}[/tex] → A
Rational expression are written as fractions. The simplified form of the expression is [tex]\frac{x-1}{x+4}[/tex]
Rational expression are written as fractions.
Given the rational expression
[tex]\dfrac{x^2-4x+3}{x^2+x-12}[/tex]
Factorize the numerator and denominator
[tex]=\dfrac{x^2-4x+3}{x^2+x-12}\\=\dfrac{x^2-3x-x+3}{x^2+4x-3x-12}\\=\frac{(x-3)(x-1)}{(x+4(x-3)} \\=\frac{x-1}{x+4}[/tex]
Hence the simplified form of the expression is [tex]\frac{x-1}{x+4}[/tex]
Learn more on rational fractions here; https://brainly.com/question/12088221
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