Respuesta :

Answer:

A

Step-by-step explanation:

Given

[tex]\frac{x^2-4x+3}{x^2+x-12}[/tex]

Factorise the numerator and denominator

x² - 4x + 3 = (x - 1)(x - 3)

x² + x - 12 = (x + 4)(x - 3), thus

= [tex]\frac{(x-1)(x-3)}{(x+4)(x-3)}[/tex] ← cancel (x - 3) on numerator/denominator

= [tex]\frac{x-1}{x+4}[/tex] → A

Rational expression are written as fractions. The simplified form of the expression is [tex]\frac{x-1}{x+4}[/tex]

Rational expressions

Rational expression are written as fractions.

Given the rational expression

[tex]\dfrac{x^2-4x+3}{x^2+x-12}[/tex]

Factorize the numerator and denominator

[tex]=\dfrac{x^2-4x+3}{x^2+x-12}\\=\dfrac{x^2-3x-x+3}{x^2+4x-3x-12}\\=\frac{(x-3)(x-1)}{(x+4(x-3)} \\=\frac{x-1}{x+4}[/tex]

Hence the simplified form of the expression is [tex]\frac{x-1}{x+4}[/tex]

Learn more on rational fractions here;  https://brainly.com/question/12088221

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