Respuesta :

Answer: 12000 kg m/s

Explanation:

According to the Impulse-Momentum Theorem, we have:

[tex]F \Delta t= \Delta p[/tex]

Where:

[tex]F=3000 N[/tex] is the exerted force

[tex]\Delta t=4 s[/tex] is the time interval

[tex] \Delta p[/tex] is the change in momentum or impulse

Then:

[tex](3000 N)(4 s)= \Delta p[/tex]

[tex]\Delta p=12000 kg m/s[/tex]  This is the impulse impacted on the object

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