Question

Suppose a circle has a varying radius of r inches and a square has a varying side length of s inches. Let D represent how much greater the area of the circle is than the area of the square (in square inches). Write a formula that expresses D in terms of r and s .

Answer 1

Answer:

Step-by-step explanation:

Answer 2

A formula that expresses D in terms of r and s is D = πr² - s²

What is the area of the circle?

A = π × r²

where r is the radius of the circle

What is the area of the square?

A = a²

where 'a' represents the side length of the square

For given example,

A circle has a varying radius of 'r' inches and a square has a varying side length of 's' inches.

Area of circle would be,

⇒ A = πr² square inches

Also, the area of the square would be,

⇒ A = s² square inches

Let D represent how much greater the area of the circle is than the area of the square (in square inches).

⇒ D = πr² - s²

Therefore, a formula that expresses D in terms of r and s is D = πr² - s²

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