Question

write the equation of a line that is perpendicular to x=-6 and that passes through the point (-1 -2)

Answer 1

Equation of the line perpendicular to x = -6 is y = -2

Step-by-step explanation:

The equation of a line in the slope-intercept force is

$y-y_0 = m(x-x_0)$

where

m is the slope

$(x_0,y_0)$ are the coordinates of a point on the line

In this problem, we have already a point on the line:

$(x_0,y_0)=(-1,-2)$

Concerning the slope, we are told that the line is perpendicular to the line

x = -6

This line is a vertical line: therefore, our line must be a horizontal line, so its slope is

$m=0$

So now we can find the equation of the line:

$y-(-2)=0(x-(-1)\\y+2=0\\y=-2$

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