75 % free throws are made by Morton
Solution:
Given that Morton made 36 out of 48 free throws last season
To find: Percent of free throws made by Morton
From given statement,
total number of throws = 48
throws made by morton = 36
Thus the percent of free throws made by Morton is given as:
[tex]percent = \frac{\text{number of throws made}}{\text{total number of throws}} \times 100[/tex]
Substituting the values, we get
[tex]percent = \frac{36}{48} \times 100\\\\percent = 0.75 \times 100 = 75 %[/tex]
Thus 75 % of his free throws are made by Morton
