Answer:
initial and final temperatures of both the water and metal, mass of the metal, and mass of the water
Explanation:
Heat lost by the metal, [tex]Q = mc(t_{2} - t_{1})[/tex]
Heat gained by the water in the calorimeter, [tex]Q_{w} = m_{w}c_{w}(t_{2w} - t_{1w})[/tex]
For energy to be conserved in the system, the heat lost by the metal will equal the heat gain by the water in the calorimeter.
[tex]mc(t_{2} - t_{1}) = m_{w}c_{w}(t_{2w} - t_{1w})[/tex]
Where,
m is the mass of the metal
c is specific heat capacity of the metal
t₂ is the final temperature of the metal
t₁ is the initial temperature of the metal
[tex]m_{w} [/tex] is the mass of the water
[tex]c_{w} [/tex] is specific heat capacity of water
[tex]t_{2w} [/tex] is the final temperature of water
[tex]t_{1w} [/tex] is the initial temperature of water
From the question given, specific heat capacity of the water is known, the quantities to be measured are;
Initial and final temperatures of both the water and metal,
Mass of the metal, and mass of the water