Question

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

2x2(6x – 1) + 3(6x – 1)
2x2(6x – 1) – 3(6x – 1)
6x(2x2 – 3) – 1(2x2 – 3)
6x(2x2 + 3) + 1(2x2 + 3)

Answer 1

Option A

$2x^2(6x-1) + 3(6x-1)$ is one way to determine the factors of $12x^3-2x^2+18x-3$ by grouping

Solution:

Factoring by grouping means that you will group terms with common factors before factoring

Given expression is:

$12x^3-2x^2+18x-3$

Group the first two terms together and then the last two terms together.

$(12x^3-2x^2)+(18x-3)$

We can see that $2x^2$ is common in first two terms

And 3 is common in last two terms

Factor them out

$(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)$

$2x^2(6x-1) + 3(6x-1)$

Thus option A is correct

Answer 2

Answer:

is one way to determine the factors of  by grouping

Solution:

Factoring by grouping means that you will group terms with common factors before factoring

Given expression is:

Group the first two terms together and then the last two terms together.

We can see that  is common in first two terms

And 3 is common in last two terms

Factor them out

Step-by-step explanation: