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Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that of satellite A. What is the speed of Satellite B?

A. vA.9
B. vA/3
C. 3vA
D. 9vA

Respuesta :

Answer:

option B

Explanation:

given,

Satellite B has an orbital radius nine times that of satellite A.

R' = 9 R

now, orbital velocity of the satellite A

[tex]v_a =\sqrt{\dfrac{GM}{R}}[/tex]........(1)

now, orbital velocity of satellite B

[tex]v_b=\sqrt{\dfrac{GM}{R'}}[/tex]

[tex]v_b=\sqrt{\dfrac{GM}{9R}}[/tex]

[tex]v_b=\dfrac{1}{3}\sqrt{\dfrac{GM}{R}}[/tex]

from equation 1

[tex]v_b=\dfrac{v_a}{3}[/tex]

hence, the correct answer is option B

The speed of satellite B will be "[tex]\frac{V_A}{3}[/tex]".

According to the question,

The orbital speed of satellite A will be:

→ [tex]V_A = \sqrt{\frac{9M}{R_A} }[/tex]

if,

  • [tex]R_B = 9R_A[/tex]

then,

Speed of satellite B will be:

→ [tex]V_B = \sqrt{\frac{9M}{9R_A} }[/tex]

        [tex]= \frac{1}{3} V_A[/tex]

        [tex]= \frac{V_A}{3}[/tex]

Thus the above answer i.e., "option B" is right.

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