Respuesta :
Answer:
option B
Explanation:
given,
Satellite B has an orbital radius nine times that of satellite A.
R' = 9 R
now, orbital velocity of the satellite A
[tex]v_a =\sqrt{\dfrac{GM}{R}}[/tex]........(1)
now, orbital velocity of satellite B
[tex]v_b=\sqrt{\dfrac{GM}{R'}}[/tex]
[tex]v_b=\sqrt{\dfrac{GM}{9R}}[/tex]
[tex]v_b=\dfrac{1}{3}\sqrt{\dfrac{GM}{R}}[/tex]
from equation 1
[tex]v_b=\dfrac{v_a}{3}[/tex]
hence, the correct answer is option B
The speed of satellite B will be "[tex]\frac{V_A}{3}[/tex]".
According to the question,
The orbital speed of satellite A will be:
→ [tex]V_A = \sqrt{\frac{9M}{R_A} }[/tex]
if,
- [tex]R_B = 9R_A[/tex]
then,
Speed of satellite B will be:
→ [tex]V_B = \sqrt{\frac{9M}{9R_A} }[/tex]
[tex]= \frac{1}{3} V_A[/tex]
[tex]= \frac{V_A}{3}[/tex]
Thus the above answer i.e., "option B" is right.
Learn more about orbital here:
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