A bag contains 7 red marbles, 6 blue marbles and 4 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be red?

Respuesta :

frika

Answer:

5.1%

Step-by-step explanation:

A bag contains 7 red marbles, 6 blue marbles and 4 green marbles, 17 marbles in total.

Number of red marbles = 7

Number of all marbles = 17

Number of choices 3 red marbles out of 7 red marbles [tex]=C^7_3=\dfrac{7!}{3!(7-3)!}=\dfrac{7!}{3!\cdot 4!}=35[/tex]

Number of choices 3 marbles out of 17 marbles [tex]=C^{17}_3=\dfrac{17!}{3!(17-3)!}=\dfrac{17!}{3!\cdot 14!}=17\cdot 8\cdot 5=680[/tex]

The probability that all three marbles drawn will be red is

[tex]\dfrac{35}{680}=\dfrac{7}{136}\approx 0.0514705\approx 5.1\%[/tex]

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