Question

A motorcycle has a mass of 2.50×10^2. A constant force is exerted on it for 60.0s. The motorcycles initial velocity is 6.00 m/s and its velocity 28.0 m/s. What is it’s change in momentum?

Answer 1

The change in momentum is 5500 kg m/s

Explanation:

The change in momentum of an object is given by

$\Delta p = m(v-u)$

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have:

$m=2.50\cdot 10^2 kg$ (mass of the motorcycle)

$v=28.0 m/s$ (final velocity)

$u=6.0 m/s$ (initial velocity)

Therefore, the change in momentum is

$\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s$

Learn more about change in momentum:

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