A (non-aqueous ) solution is found to have a molarity of 2.50 molal and experiences a freezing point depression of 5.20 degree C. What is kf of the solvent (in degrees c/m) ?

Respuesta :

Answer:

Kf for the solvent is 2.08°C / m

Explanation:

Formula for lowing point depression is:

ΔT = Kf . m

Then, the ΔT is 5.20°C and the molality is found to be, 2.50 m

5.20°C = Kf . 2.50 m

5.20°C /2.50 m = Kf  →  2.08°C / m

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