at -11°c a sample of carbon monoxide gas exerts a pressure of 0.37 atm. What is the pressure when the volume of the gas is reduced to one third or the original value at the same temperature?​

Respuesta :

Answer: The pressure will be 1.11atm

Explanation:

V1 = V

P1 = 0.37 atm

V2 = (1/3)V

P2 =?

P1V1 = P2V2

0.37 x V = P2 x (1/3)V

P2 = (0.37 x V) / (1/3)V

P2 = 0.37 x 3 = 1.11atm

The pressure will be 1.11 atm.

Based on the given information,  

• A sample of carbon dioxide gas exerts a pressure of 0.37 atm.

• The volume of the gas is reduced to one-third, therefore, let us consider that the initial volume of the gas is V and the final volume of the gas will be V/3.

Now based on ideal gas law,  

PV=nRT

• At constant temperature, PV will be constant.  

So, P₁V₁ = P₂V₂

Now putting the values we get,  

0.37atm×V = P₂×V/3

3×0.37 = P₂

P₂ = 1.11 atm

Thus, when the volume of the gas is reduced to one-third, the pressure of the gas will become 1.11 atm.

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