Respuesta :
This is an incomplete question, here is a complete question.
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately [tex]2.15\times 10^6m/s[/tex]?
Find the force acting on the electron as it revolves in a circular orbit of radius [tex]5.34\times 10^{-11}m[/tex].
Answer : The force acting on electron is, [tex]7.9\times 10^{-8}N[/tex]
Explanation :
Formula used :
[tex]F=\frac{mv^2}{r}[/tex]
where,
F = force acting on electrons
m = mass of electrons = [tex]9.1\times 10^{-31}kg[/tex]
v = speed of electron = [tex]2.15\times 10^6m/s[/tex]
r = radius of circular orbit = [tex]5.34\times 10^{-11}m[/tex]
Now put all the given values in the above formula, we get:
[tex]F=\frac{(9.1\times 10^{-31}kg)\times (2.15\times 10^6m/s)^2}{5.34\times 10^{-11}m}[/tex]
[tex]F=7.9\times 10^{-8}N[/tex]
Thus, the force acting on electron is, [tex]7.9\times 10^{-8}N[/tex]
