Answer: b) less than; number of particles of solute
Explanation:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
[tex]\frac{p^o-p_s}{p^o}=i\times x_2[/tex]
where,
[tex]\frac{p^o-p_s}{p^o}[/tex]= relative lowering in vapor pressure
i = Van'T Hoff factor
[tex]x_2[/tex] = mole fraction of solute =[tex]\frac{\text {moles of solute}}{\text {total moles}}[/tex]
a) 1 M KI
i= 2 as it is a electrolyte and dissociates to give two ions.
[tex]KI\rightarrow K^++I^-[/tex]
b) 1 M glucose
i= 1 as it is a non electrolyte and does not dissociate to give ions.
Thus as number of particles in 1 M KI is higher, the lowering in vapor pressure will be more.