Question

A 80 g particle is moving to the left at 22 m/s . How much net work must be done on the particle to cause it to move to the right at 38 m/s ?

Answer 1

Answer:

W= 38.4 J

Explanation:

Given that

m = 80 g= 0.08 kg

Initial speed ,u= 22 m/s

Final speed ,v= 38 m/s

The change in the kinetic energy of the particle

$\Delta KE=\dfrac{1}{2}m(v^2-u^2)$

$\Delta KE=\dfrac{1}{2}\times 0.08\times (38^2-22^2)\ J$

ΔKE= 38.4 J

We know that

Work done by all the forces =Change in the kinetic energy

That is why net work done = 38.4 J.

W= 38.4 J

Therefore the answer will be 38.4 J.