Answer:
θ = sininverse(155/200)
θ = 50.8°
Therefore the arm of the crane must be set at 50.8°
Step-by-step explanation:
Given;
The length of crane arm = 200ft
The height of building = 160ft
The initial height of the crane = 5ft
Therefore, the relative height of the building from the crane can be written as;
h = 160ft - 5ft = 155ft
The angle θ that at which the crane makes with the horizontal can be written as;
Sinx = opposite/hypothesis = 155ft/200ft
θ = sininverse(155/200)
θ = 50.8°
Therefore the arm of the crane must be set at 50.8°
