Answer:
Velocity of truck will be 20.287 m /sec
Explanation:
We have given mass of the truck m = 4000 kg
Radius of the turn r = 70 m
Coefficient of friction [tex]\mu =0.6[/tex]
Centripetal force is given [tex]F=\frac{mv^2}{r}[/tex]
And frictional force is equal to [tex]F_{frictional}=\mu mg[/tex]
For body to be move these two forces must be equal
So [tex]\frac{mv^2}{r}=\mu mg[/tex]
[tex]v=\sqrt{\mu rg}=\sqrt{0.6\times 70\times 9.8}=20.287m/sec[/tex]
