Let X denote daily work hours. Suppose that for the sample of workers you​ have, the average daily work hours are 8​ hours, with a standard deviation of 5. Suppose now let Z denote weekly work​ hours, find the mean and standard deviation for Z​ (assuming everyone works 5 days per week in your​ sample).

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Answer:

The mean for Z is 40.

The standard deviation for Z is 25.                      

Step-by-step explanation:

We are given the following in the question:

X:  daily work hours.

The average daily work hours are 8​ hours, with a standard deviation of 5.

[tex]E(x) = 8\\S.D(X) = 5[/tex]

[tex]Var(X) = 5^2 = 25[/tex]

Z denote weekly work​ hours.

We have to find the mean and standard deviation for Z.

[tex]E(Z) =E(5x) = 5\tims E(X) = 5\times 8 = 40[/tex]

The mean for Z is 40.

We use the property:

[tex]Var(ax) = a^2Var(x)[/tex]

[tex]Var(Z) = Var(5x) = 5^2(Var(X)) = 25\times 25 = 625\\S.D(Z) = \sqrt{625} = 25[/tex]

Thus, the standard deviation for Z is 25.

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