Question

A 10-m-long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 34 m/s when a 60 kg skydiver drops out by releasing his grip on the glider. What is the gliders speed just after the skydiver lets go? Express your answer to two significant figures and include the appropriate units.

Answer 1

Answer:

34 m/s

Explanation:

m = Mass of glider with person = 680 kg

v = Velocity of glider with person = 34 m/s

$m_1$ = Mass of glider without person = 680-60 kg

$v_1$ = Gliders speed just after the skydiver lets go

$m_2$ = Mass of person = 60 kg

$v_2$ = Velcotiy of person = 34 m/s

As the linear momentum of the system is conserved

$m_1v_1+m_2v_2=mv\\\Rightarrow v_1=\dfrac{mv-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{680\times 34-60\times 34}{680-60}\\\Rightarrow v_1=34\ m/s$

The gliders speed just after the skydiver lets go is 34 m/s

Answer 2

The gliders speed just after the skydiver lets go is 37.3 m/s.

The given parameters;

• mass of the glider with the skydiver, m₁ = 680 kg
• initial velocity of the glider, v₁ = 34 m/s
• mass of the skydiver, m = 60 kg

Apply the principle of conservation of linear momentum to determine the speed of the glider when the skydiver is released.

mass of the glider without the person, m₂ = 680 kg - 60 kg = 620 kg

initial momentum of the glider = final momentum of the glider

$m_1 v_1 = m_2v_2\\\\v_2 = \frac{m_1 v_1}{m_2} \\\\v_2 = \frac{680 \times 34}{620} \\\\v_2 = 37.3 \ m/s$

Thus, the gliders speed just after the skydiver lets go is 37.3 m/s.

Learn more here:https://brainly.com/question/24424291