Answer: A. 0.4207
Step-by-step explanation:
Given : The lifetime of a 2-volt non-rechargeable battery in constant use has a Normal distribution with a mean of 516 hours and a standard deviation of 20 hours.
i.e. [tex]\mu=516[/tex]
[tex]\sigma=20[/tex]
Let x denotes the lifetime of a 2-volt non-rechargeable battery in constant use.
Then , the probability of batteries with lifetimes exceeding 520 hours is approximately:-
[tex]P(X>520)=1-P(x\leq520)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{520-516}{20})\\\\=1-P(z\leq0.2)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\ =1-0.5793\ \ [\text{By z-table}]\\\\=0.4207[/tex]
Hence, the proportion of batteries with lifetimes exceeding 520 hours is approximately 0.4207.
∴ Correct option is A. 0.4207