Cost of one hosta is $11 and one pot of ivy is $4.
Step-by-step explanation:
Let,
Cost of one hosta = x
Cost of one pot of ivy = y
According to given statement;
3x+5y=53 Eqn 1
x+7y=39 Eqn 2
Multiplying Eqn 2 by 3
[tex]3(x+7y=39)\\3x+21y=117\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 1 from Eqn 3
[tex](3x+21y)-(3x+5y)=117-53\\3x+21y-3x-5y=64\\16y=64[/tex]
Dividing both sides by 16
[tex]\frac{16y}{16}=\frac{64}{16}\\y=4[/tex]
Putting y=4 in Eqn 2
[tex]x+7(4)=39\\x+28=39\\x=39-28\\x=11[/tex]
Cost of one hosta is $11 and one pot of ivy is $4.
Keywords: linear equation, elimination method
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