Respuesta :

Cost of one hosta is $11 and one pot of ivy is $4.

Step-by-step explanation:

Let,

Cost of one hosta = x

Cost of one pot of ivy = y

According to given statement;

3x+5y=53     Eqn 1

x+7y=39       Eqn 2

Multiplying Eqn 2 by 3

[tex]3(x+7y=39)\\3x+21y=117\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 1 from Eqn 3

[tex](3x+21y)-(3x+5y)=117-53\\3x+21y-3x-5y=64\\16y=64[/tex]

Dividing both sides by 16

[tex]\frac{16y}{16}=\frac{64}{16}\\y=4[/tex]

Putting y=4 in Eqn 2

[tex]x+7(4)=39\\x+28=39\\x=39-28\\x=11[/tex]

Cost of one hosta is $11 and one pot of ivy is $4.

Keywords: linear equation, elimination method

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