Answer:
See explanation
Step-by-step explanation:
William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive.
Factor number 24 and 60:
[tex]24=2\cdot 12=2\cdot 2\cdot 6=2\cdot 2\cdot 2\cdot 3=2^3\cdot 3\\ \\60=2\cdot 30=2\cdot 2\cdot 15=2\cdot 2\cdot 3\cdot 5=2^2\cdot 3\cdot 5[/tex]
Find the greatest common factor
[tex]GCF(24,60)=2^2\cdot 3=12[/tex]
Hence, the greatest number of bags William can make is 12.
Each of these bags will have [tex]24\div 12=2[/tex] cans of fruit and [tex]60\div 12=5[/tex] cans of vegetables.
If he made fewer bags, 6 bags, each of these bags will have [tex]24\div 6=4[/tex] cans of fruit and [tex]60\div 6=10[/tex] cans of vegetables.
If he made fewer bags, 4 bags, each of these bags will have [tex]24\div 4=6[/tex] cans of fruit and [tex]60\div 4=15[/tex] cans of vegetables.
If he made fewer bags, 3 bags, each of these bags will have [tex]24\div 3=8[/tex] cans of fruit and [tex]60\div 3=20[/tex] cans of vegetables.
If he made fewer bags, 2 bags, each of these bags will have [tex]24\div 2=12[/tex] cans of fruit and [tex]60\div 2=30[/tex] cans of vegetables.