Question

0.10-kilogram model rocket’s engine is designed to deliver an impulse of 6.0 newton-seconds. If the rocket engine burns for 0.75 second, what average force does it produce?

Answer 1

Answer:

8.0 N

Explanation:

Force: This can be defined as the mass of a body and its acceleration. The S.I unit of Force is Newton (N).

Mathematically, Fore is expressed as

F = ma ........................... equation 1

Where F = force, m = mass, a = acceleration.

and

I = mΔv

Δv = I/m ............................ Equation 2

Where I = impulse, m = mass, Δv = change in velocity

Given: I = 6.0 Newton-seconds, m = 0.1 kilogram.

Substituting into equation 2

Δv = 6.0/0.1

Δv = 60 m/s.

But

a = Δv/t

where t = time = 0.75 seconds.

a = 60/0.75

a = 80 m/s²

Substitute the values of a and m into equation 1.

F = 0.1(80)

F = 8.0 N.

Thus the average force produced = 8.0 N

Answer 2

The average force produced by the rocket's engine is 8 N.

We can solve the problem above, Using the formula of impulse of a force.

⇒ Formula:

• I = Ft................ Equation 1

⇒ Where:

• I = Impulse delivered by the rocket's engine

• F = The average force produced by the engine

• t = time

⇒ make F the subject of equation 1

• F = I/t................. Equation 2

From the question,

⇒ Given:

• I = 6.0 Ns
• t = 0.75 s

⇒ Substitute these values into equation 2

• F = 6.0/0.75
• F = 8 N

Hence, the average force produced by the rocket's engine is 8 N

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