Answer:
[tex]\frac{3}{8}[/tex] when fully reduce it contains only 1 number of [tex]\frac{1}{4}[/tex] in it.
Step-by-step explanation:
Given;
[tex]\frac{3}{8}[/tex]
We need to find the given how many [tex]\frac{1}{4}[/tex] are there in given equation when reduced.
Solution:
First we will reduce the numerator.
Factor of 3 = [tex]1\times 3[/tex]
Factor of 8 = [tex]2\times 4[/tex]
Now after substituting the same we get;
So we can say that;
[tex]\frac{3}{8}= \frac{1\times3}{2\times4}=\frac{3}{2}\times\frac{1}{4}[/tex]
Hence we can say that [tex]\frac{3}{8}[/tex] when fully reduce it contains only 1 number of [tex]\frac{1}{4}[/tex] in it.